z^2/1=z/5+4/-5

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Solution for z^2/1=z/5+4/-5 equation:


z in (-oo:+oo)

(z^2)/1 = z/5+4/(-5) // - z/5+4/(-5)

(z^2)/1-(z/5)-(4/(-5)) = 0

z^2-(z/5)+4/5 = 0

z^2-1/5*z+4/5 = 0

DELTA = (-1/5)^2-(4/5*1*4)

DELTA = -79/25

DELTA < 0

z belongs to the empty set

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